(x+3)^2=2^2+6x+9

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Solution for (x+3)^2=2^2+6x+9 equation: 



(x+3)^2=2^2+6x+9

We move all terms to the left:

(x+3)^2-(2^2+6x+9)=0

We get rid of parentheses

(x+3)^2-6x-9-2^2=0

We add all the numbers together, and all the variables

-6x+(x+3)^2-13=0

We move all terms containing x to the left, all other terms to the right

-6x+(x+3)^2=13

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